(D) Given power output $P_{out} = 16 \,MW = 16 \times 10^6 \,W$.Efficiency $\eta = 50\% = 0.5$.The total power required from fission $P_{in} = \frac{P

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(D) Given power output $P_{out} = 16 \,MW = 16 \times 10^6 \,W$.Efficiency $\eta = 50\% = 0.5$.The total power required from fission $P_{in} = \frac{P_{out}}{\eta} = \frac{16 \times 10^6}{0.5} = 32 \times 10^6 \,W$.Energy released per fission $E = 200 \,MeV = 200 \times 1.6 \times 10^{-13} \,J = 3.2 \times 10^{-11} \,J$.The number of fissions per second $n = \frac{P_{in}}{E} = \frac{32 \times 10^6}{3.2 \times 10^{-11}} = 10^{18} \,fissions/s$.

Class 12 Physics Nuclei Nuclear Fission, Fusion and Nuclear Reactor

Medium

The energy released by the fission of a single uranium nucleus is $200 \,MeV$. The number of fissions of uranium nucleus per second required to produce $16 \,MW$ of power is (Assume efficiency of the reactor is $50\%$).

A
$2 \times 10^6$
B
$2.5 \times 10^6$
C
$5 \times 10^6$
D
$1 \times 10^{18}$

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Nuclei

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Nuclear Fission, Fusion and Nuclear Reactor

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The energy released by the fission of a single uranium nucleus is $200 \,MeV$. The number of fissions of uranium nucleus per second required to produce $16 \,MW$ of power is (Assume efficiency of the reactor is $50\%$).

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Choosing the correct option, complete the given nuclear fusion reaction that occurs in the sun.${ }_1^3 H +{ }_1^3 H \rightarrow{ }_2^4 He +{ }_1^1 H +{ }_1^1 H +$ . . . . . . . (in $\text{ MeV}$)

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Choosing the correct option, complete the given nuclear fusion reaction that occurs in the sun.
${ }_1^3 H +{ }_1^3 H \rightarrow{ }_2^4 He +{ }_1^1 H +{ }_1^1 H +$ . . . . . . . (in $\text{ MeV}$)